For max 25V input and 5V output: Choose R1 = 10kΩ, R2 = 5.6kΩ Then, ( V_out = 25 \times \frac5.615.6 \approx 8.97V ) — too high. Better: ( R1 = 20k\Omega, R2 = 5k\Omega ) ( V_out = 25 \times \frac525 = 5V ) – perfect.
Have you created your own voltage sensor simulation? Share your experience in the comments below. voltage sensor proteus library
void loop() int adcValue = analogRead(A0); float voltage = (adcValue / 1023.0) * 5.0; // Voltage at divider output float inputVoltage = voltage * ((20000 + 5000) / 5000.0); // Rescale Serial.print("Input Voltage: "); Serial.print(inputVoltage); Serial.println(" V"); delay(500); For max 25V input and 5V output: Choose R1 = 10kΩ, R2 = 5
But can you find a dedicated "Voltage Sensor" component in Proteus’s default library? The answer is nuanced. While Proteus does not always have a generic part named "VOLTAGE SENSOR," it provides multiple powerful methods to simulate voltage sensing accurately. Share your experience in the comments below
Run the simulation. Open Virtual Terminal. You will see the computed input voltage.
Introduction In the realm of electronic circuit design and simulation, Proteus Design Suite stands as a cornerstone for engineers, hobbyists, and students. One of the most critical components in modern electronics—especially in microcontroller-based projects, IoT devices, and battery management systems—is the voltage sensor .