M = 18. Standard greedy uses 10+5+3 = 3 coins. But 18-10=8, and 8 is not divisible by 3, so allowed. If M=20, standard: 10+10 =2 coins, but after first 10, remainder=10 (not divisible by 3) → allowed. If M=15, standard: 10+5=2 coins, but remainder after 10 is 5 (not div by 3) → allowed. Actually this twist made it tricky.
A teacher writes a sentence. She wants to reverse the words that have an even length, but leave odd-length words unchanged. Print the final sentence. Example: Input: "Hello World Python" → Output: "olleH World nohtyP" Tcs Coding Questions 2021
Write a program to find the sum of all prime numbers between two given integers L and R (inclusive). Constraints: 1 ≤ L ≤ R ≤ 10^6. M = 18
M=13. Standard greedy: 10+3 = 2 coins. But remainder after 10 =3 (divisible by 3) → forbidden. So you must choose 5+5+3 =3 coins. If M=20, standard: 10+10 =2 coins, but after