Equilibre D 39un Solide Soumis A 3 Forces Exercice Corrige Pdf Exclusive May 2026

Magnitude of R = √(80² + 60²) = 100 N Direction: tan(θ) = R_y / R_x (in absolute) = 60/80 = 0.75 → θ ≈ 36.87° above the negative x-axis (i.e., upward left).

(Note: For the purpose of this article, we illustrate the content. In a real scenario, a download link or email capture would appear here.) The equilibrium of a solid under three forces is a cornerstone of mechanics. Understanding it requires both conceptual clarity and rigorous practice. With our exclusive PDF of corrected exercises , you move from passive reading to active mastery. Each exercise is a building block toward solving real-world static problems with confidence. Magnitude of R = √(80² + 60²) =

Equilibrium of torques: T × 2.4 = 240 → T = 100 N Using force equilibrium in x and y: Horizontal: R_x + T_x = 0 . T_x = T × (4/5) = 100 × 0.8 = 80 N (negative direction). So R_x = -80 N (to the left). Vertical: R_y + T_y – P = 0 . T_y = T × (3/5) = 60 N upward. So R_y = P – T_y = 120 – 60 = 60 N upward. Equilibrium of torques: T × 2